Home »

## Conversion

# Now synthesize your FIR filters using high-school algebra

March 07, 2012 | Kendall Castor-Perry | 222903141

**In this second part of a two-parter, the Filter Wizard aka Kendall Castor-Perry turns the process of factorizing the polynomial representation of an FIR filter into a product of quadratic and linear factors on its head and builds up complete FIR filters from small, easy-to-understand pieces.**

Page 1 of 6

**The story so far**

In Part 1 we took a regular FIR filter design and wrote down the filter coefficients in

polynomial form to get equation [1]:

Then we found all the roots of this polynomial, and used them to write down the

factorized form of the polynomial:

As a parting shot, I pointed out that there are three quadratic terms there with unity coefficients of z^0 and there are three deep nulls in the gain response of the filter, as was shown in the figures from Part 1. Lets take a deep breath and examine the responses of all these individual linear and quadratic factors, to see if there are some clues there.

Figure 1 shows the individual responses, treated as two- or three-tap FIR filters, of each of the factors in parentheses in equation [2]; the five quadratic factors marked as q1 to q5 and the four linear factors and L1 to L4. Its quite a jumble of a graph, but you dont have to be very awake to see the major salient detail: three of those quadratic factors have deep notches in the frequency response. These are indeed the three factors whose constant (z^0) coefficient is unity!

So, heres the first takeaway. In an FIR filter whose stopband contains a number of sharp nulls, each one of them comes into being because the response of one of the polynomials quadratic factors falls to zero at one frequency. Just so that we dont jump to conclusions about the particular form the factor needs to have, lets do some more algebra to make sure. Are we having fun yet?

**Figure 1:**

The frequency response of all the quadratic and linear factors of equation [2]

The frequency response of all the quadratic and linear factors of equation [2]

The frequency response of a quadratic factor used as a filter

Heres where we make an important substitution. Until now, our z has been a mystery variable with no obvious relationship to the behaviour of a sinewave. Lets introduce the expression that actually defines the z-transform. The key relationships between z , z^-1 and the frequency f of a sinewave input can be expressed in either an exponential or a trig format:

**Please login to post your comment - click here**

Related News

- No news

MOST POPULAR NEWS

- Plan to re-open Rousset fab requires investors
- Micron Italian job cuts get global criticism
- Memory, firms, fabless climb chip vendor ranking
- European Commission intervenes in Micron Italian jobs case
- S3 preps DAC product with a twist
- The Filter Wizard: on being analog AND open
- Samsung leads chip capex ranking
- Opinion: Europe must back the Rousset Phoenix
- MEMS, magnetics set to lead sensor market rebound
- Startup launches record resolution 150Mpixel sensor
- What is an ampere?
- Mentor buys Berkeley DA after Cadence lawsuit
- Jobs saved at Micron Italy, say reports
- Will China Conquer MEMS?
- Ex-Omnivision engineers form image sensor startup

Interview

Technical papers

- Sensor Hardware Technology Overview
- Hall-Effect Sensor ICs for Motor Control
- Improving Voltage Regulation without Remote Sense Wires
- Mixed Signal Design and Verification for complex SoCs
- An Introduction to Rigid-Flex PCB Design Best Practices
- 4-20 mA, Loop Powered, Thermocouple System Using ARM
- EMC Compliant RS-485 Transceiver Protection Circuits

Poll